From 383285ecd5292bf9a825e05904955b937de84cc9 Mon Sep 17 00:00:00 2001 From: Minteck Date: Sat, 4 Jun 2022 08:51:01 +0200 Subject: Initial commit --- node_modules/abbrev/abbrev.js | 61 +++++++++++++++++++++++++++++++++++++++++++ 1 file changed, 61 insertions(+) create mode 100644 node_modules/abbrev/abbrev.js (limited to 'node_modules/abbrev/abbrev.js') diff --git a/node_modules/abbrev/abbrev.js b/node_modules/abbrev/abbrev.js new file mode 100644 index 0000000..7b1dc5d --- /dev/null +++ b/node_modules/abbrev/abbrev.js @@ -0,0 +1,61 @@ +module.exports = exports = abbrev.abbrev = abbrev + +abbrev.monkeyPatch = monkeyPatch + +function monkeyPatch () { + Object.defineProperty(Array.prototype, 'abbrev', { + value: function () { return abbrev(this) }, + enumerable: false, configurable: true, writable: true + }) + + Object.defineProperty(Object.prototype, 'abbrev', { + value: function () { return abbrev(Object.keys(this)) }, + enumerable: false, configurable: true, writable: true + }) +} + +function abbrev (list) { + if (arguments.length !== 1 || !Array.isArray(list)) { + list = Array.prototype.slice.call(arguments, 0) + } + for (var i = 0, l = list.length, args = [] ; i < l ; i ++) { + args[i] = typeof list[i] === "string" ? list[i] : String(list[i]) + } + + // sort them lexicographically, so that they're next to their nearest kin + args = args.sort(lexSort) + + // walk through each, seeing how much it has in common with the next and previous + var abbrevs = {} + , prev = "" + for (var i = 0, l = args.length ; i < l ; i ++) { + var current = args[i] + , next = args[i + 1] || "" + , nextMatches = true + , prevMatches = true + if (current === next) continue + for (var j = 0, cl = current.length ; j < cl ; j ++) { + var curChar = current.charAt(j) + nextMatches = nextMatches && curChar === next.charAt(j) + prevMatches = prevMatches && curChar === prev.charAt(j) + if (!nextMatches && !prevMatches) { + j ++ + break + } + } + prev = current + if (j === cl) { + abbrevs[current] = current + continue + } + for (var a = current.substr(0, j) ; j <= cl ; j ++) { + abbrevs[a] = current + a += current.charAt(j) + } + } + return abbrevs +} + +function lexSort (a, b) { + return a === b ? 0 : a > b ? 1 : -1 +} -- cgit